Find the rate of change of the area of a square whose side is 8 cm long, if this side length is increasing at 2 cm/min
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Step-by-step explanation:
ds/dt = 5
A = s^2
Let A be area in cm, Let s be the length of the side, Let t be the time in seconds
So we are looking for dA/dt when s = 10
dA/dt = d/dt (s^2)
= 2s(ds/dt)
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