Find the rate of consumption Of H2 If The Rate Of Formation Of Ammonia Is 34gm/hour
The Reaction Is :N2(g)+3H2(g) ⇌ 2NH3(g)
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Explanation:
1/2[dNH3]/dt=-1/3[dH2]/dt
Given [dNH3]/dt= 34
[dH2]/dt=3/2×[dNH3]/dt
=3×34/2
=51gm/hour
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