Find the rate of interest at which, a sum of money becomes 9/4 times in 2 years.
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Answered by
4
let P=x
A=9/4x
Sl=9/4x-x=5x/4
T=2yrs
R=SI×100/(P×T)=(5x/4×100)/(x×2)
R=62.5
required ans=62.5%
A=9/4x
Sl=9/4x-x=5x/4
T=2yrs
R=SI×100/(P×T)=(5x/4×100)/(x×2)
R=62.5
required ans=62.5%
Answered by
0
Let Principal be ₹x
Amount=(9/4)*x=P+I
I=(9/4)*x-P=(9/4)*x-x=(5/4)*x
T=2 yrs
I=(P*r*t)/100
=>(5/4)x=(x*r*2)/100
=>125x=x*r*2
=>125 = r*2
=>r=62.5%
Please mark the brainliest.Its urgent
Amount=(9/4)*x=P+I
I=(9/4)*x-P=(9/4)*x-x=(5/4)*x
T=2 yrs
I=(P*r*t)/100
=>(5/4)x=(x*r*2)/100
=>125x=x*r*2
=>125 = r*2
=>r=62.5%
Please mark the brainliest.Its urgent
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