Math, asked by Thasleemasiraj, 7 months ago

Find the rate of interest at which an amount of Rs. 12000 will become
Rs. 15000 at the end of 10year​

Answers

Answered by anointajames
3

Answer:

2.5%

Step-by-step explanation:

Given,

P = 12000

T = 10

S.I = A - P = 15000 - 12000 = 3000

Simple Interest Formula -

S.I. = (PRT)/100

Substitute values, we get -

3000 = (12000)R(10)/100

Solve for R -

3 = (12 x R)/10

30 = 12 x R

30/12 = R

15/6 = R

5/2 = R

R = 2.5%

Answered by Anonymous
1

Answer:

Given,

P = 12000

A = 15000

T = 10 years

SI = (A-P) = 15000-12000 = 3000

Simple interest formula

s.i = (PRT)/100

substitute values we get

3000 = (12000)R(10)/100

Solve to get value of R

3 = (12 × R)/10

30 = 12 × R

30/12 = R

15/6 = R

5/2 = R

R = 2.5%

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