Find the Rate of Interest for a Given Sum of Money
A sum of money amounts to Rs. 5,200 in 5 years and Rs. 5,680 in 7 years at simple interest. What was the rate of interest charged per annum? a) 3% b) 4% c) 5% d) 6%
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The rate of interest charged is 6% and the amount is Rs. 4000.
Let us look at how to arrive at this.
If x is the principal amount and r is the rate of interest, then,
Interest in 5 years, i1 = 5xr/100 and T1 = x+i1 = x + 5xr/100 = 5200
On similar lines, we get i2 = 7xr/100 and T2 = x+7xr/100 = 5680
So, we have a sequence of two equations and two unknowns, x and r.
Let us solve for x and r.
From T2 and T1, we get
5680 = x+7xr/100 ---- (1)
5200 = x+5xr/100 ---- (2)
Subtracting (2) from (1), we get
480 = 2xr/100
Or xr = 24000
or r = 24000/x
Substituting the value of r = 24000/x in (2), we get
5200 = x + 5*x*24000/x/100
5200 = x + 5*240 = x+1200
Therefore x = 5200 - 1200 = 4000
Substituting the value of x = 4000 in r = 24000/x, we get
r = 24000/4000 = 6%.
Hence, the rate of interest is 6% and principal amount is Rs. 4000.
Please mark it as brainly.
Let us look at how to arrive at this.
If x is the principal amount and r is the rate of interest, then,
Interest in 5 years, i1 = 5xr/100 and T1 = x+i1 = x + 5xr/100 = 5200
On similar lines, we get i2 = 7xr/100 and T2 = x+7xr/100 = 5680
So, we have a sequence of two equations and two unknowns, x and r.
Let us solve for x and r.
From T2 and T1, we get
5680 = x+7xr/100 ---- (1)
5200 = x+5xr/100 ---- (2)
Subtracting (2) from (1), we get
480 = 2xr/100
Or xr = 24000
or r = 24000/x
Substituting the value of r = 24000/x in (2), we get
5200 = x + 5*x*24000/x/100
5200 = x + 5*240 = x+1200
Therefore x = 5200 - 1200 = 4000
Substituting the value of x = 4000 in r = 24000/x, we get
r = 24000/4000 = 6%.
Hence, the rate of interest is 6% and principal amount is Rs. 4000.
Please mark it as brainly.
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