Question

find the rate of interest for the following time = 1 years , SI = ₹1200 , p = ₹ 300​0

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Answer 1

Answer:

SI= PRT/100

1200 = 3000*R*1/100

1200= 30R

R = 40

Rate of interest = 40%

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Answer 2

Si = ₹ 1200

P = ₹ 3000

T = 1 year

$R = \frac{1200 \times 100}{3000 \times 1}$

$\: \: \: \: = 40\%$