Question

Find the rate of interest, if P = Rs. 125,000, T= 3 years and I = Rs. 37,500.

Answer 1

➤ Given :-

Principle (P) :- ₹ 125000

Time (T) :- 3 years

Interest (I) :- ₹ 37500

➤ To Find :-

Rate of interest for the given sum.........

➤ Formula :-

$\bf\orange {\underline {\underline {si \times 100 \div p \times t}}}$

➤ Solution :-

$⇢ \sf \frac{si \times 100}{p \times t}$

$⇢ \sf \frac{37500 \times 100}{125000 \times 3}$

$⇢ \sf \frac{{\cancel{3500}} \times 100}{ \cancel{125000} \times 3} = \frac{35 \times 100}{1250 \times 3}$

$⇢ \sf \cancel\frac{3500}{3750} = \frac{14}{15} = 0.933333333333 \bf\%$

$\Huge\therefore$The rate of interest is 0.933333333333$\bf\%$ .

Answer 2

Answer:

$\huge \bf \: given$

• Principal = ₹1,25,000
• Time = 3 years
• Simple interest = ₹37,500

$\huge \bf \: to \: find$

Rate of interest

$\huge \bf \: solution$

$\frac{si \: \times 100}{p \: \times t}$

$\frac{37500 \times 100}{125000 \times 3}$

$\frac{35 \times 100}{1250 \times 3}$

$\frac{3500}{3750}$

$\frac{14}{13} = 0.933333$