Question

Find the rate of interest when 800 fetches 130 as simple interest in 2 years 6 months​

Answer 1

Given :

• Principal money, P = 800
• Simple interest on this money, S.I. = 130
• Time for interest, t = 2 yrs 6 months = 2.5 yrs

To find :

• Rate of Interest, R =?

Formula required :

• Formula to calculate Simple interest

$\purple{\bigstar}\boxed{\sf{S.I.=\dfrac{P\times R \times t}{100}}}$

[ Where S.I. in simple interest on Principal money P, Rate of interest per annum R and t being time for interest ]

Solution :

Using formula for SImple interest

$\implies\sf{S.I.=\dfrac{P \times R \times t }{100}}$

$\implies\sf{130=\dfrac{800 \times R \times 2.5 }{100}}$

$\implies\sf{130=8 \times R \times 2.5}$

$\implies\sf{130=20 \times R }$

$\implies\sf{R=\dfrac{130}{20}}$

$\implies\boxed{\boxed{\large{\purple{\sf{R=6.5\;\;\%}}}}} \;\;\;\purple{\bigstar}$

Therefore,

• Rate of interest is 6.5 %.

Answer 2

Answer:

✡ Correct Question ✡

$\leadsto$ Find the rate of interest when Rs 800 fetches Rs 130 as simple interest in 2 years 6 months.

✡ Given ✡

$\leadsto$ Principal (P) = Rs 800

$\leadsto$ Time (T) = 2 years 3 months = 2 + $\dfrac{1}{2}$ = $\dfrac{5}{2}$ years.

$\leadsto$ Simple Interest (S.I) = Rs 130

$\leadsto$ Rate of Interest (R%) = ?

✡ Formula Used ✡

✳ S.I = $\dfrac{P × R × T}{100}$ ✳

✡ Solution ✡

✏ Given:-

• P = Rs 800
• T = $\dfrac{5}{2}$
• S.I = Rs 130

▶ According to the question,

⭐ S.I = $\dfrac{P × R × T}{100}$ ⭐

$\implies$ 130 = $\dfrac{800 × R × 5}{100 × 2}$

$\implies$ $\dfrac{130}{5}$ = 4R

$\implies$ 4R = $\dfrac{130}{5}$

$\implies$ R = $\dfrac{130}{20}$

$\implies$ R = 6.5 % per annum

Hence, the rate of interest (R%) is 6.5% per annum.

Step-by-step explanation:

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