Find the rate of interest when 800 fetches 130 as simple interest in 2 year 6 months
Answers
Answered by
10
Answer:
Step-by-step explanation:
SI =PTR/100
130=800×5×R
________
100×2
130=2R
130/2=R
6.5%=R
Answered by
13
Solution :
Given
principal ( P ) = Rs800
Time ( T ) = 2 years 6 months
=( 2 + 1/2 ) Years
= 5/2 years
Let rate of interest = R
simple interest (s.i ) = Rs130
We know that ,
(PTR)/100 = S.I
=> R = ( S.I × 100 )/( PT)
= ( 130 × 100 )/( 800 ×5/2 )
= ( 130 × 2 )/( 8 × 5 )
= 13/2
= 6½ %
= 6.5%
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