Question

find the rate of interest when rs 800 fetches rs 130 as a simple interest in 2 years 6 months

Answer 1

Answer:

The answer for your question is given below:

Step-by-step explanation:

S.I=Rs130

T=2years6months=2+21=25years

Principle = 800rupees

Rate = ?

S.I=100P×R×T

130=100800×R×25

5130=4R

4R=5130

R=20130

R=6.5%per annum

Hope this helps you..thank you

Answer 2

Here,

P = Rs 800

T = 2 years 6 months

= 5 / 2 years

Hence,

R = (I × 100) / (P × T)

= (130 × 100) / {800 × (5 / 2)} % p.a.

On simplification, we get,

= (130 × 100 × 2) / (800 × 5) % p.a.

= (130 × 2) / 40 %

= 130 / 20 % p.a.

= 13 / 2 %

= 6.5% p.a.

Therefore, the required rate of interest is 6.5% p.a.

${\fcolorbox{blue}{black}{\orange{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: DecentMortal\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}$