find the rate of interest when rupees 800 fetches rupees 130 as simple interest in 2 years 6 months?
Answers
Answered by
1
Answer:
S.I=Rs130
T=2years6months=2+
2
1
=
2
5
years
Principle = 800rupees
Rate = ?
S.I=
100
P×R×T
130=
100
800×R×
2
5
5
130
=4R
4R=
5
130
R=
20
130
R=6.5%perannum
Answered by
2
Here,
P=Rs 800
T=2 years 6 months =2
12
6
years
=2
2
1
years =
2
5
years
Hence,
R=
P×T
I×100
=
800×
2
5
130×100
% p.a.
On simplification, we get,
R=
800×5
130×100×2
% p.a.
=
40
130×2
% p.a.
=6.5% p.a.
Therefore, the required rate of interest is 6.5% p.a.
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