Question

Find the rate of interest when simple interest on Rs.1560 in 3 years is Rs.585.​

Answer 1

Step-by-step explanation:

S.I.=Rs.2730

Principal(P)=Rs.12000

Rate(R)=6

2

1

%=

2

13

% p.a.

∴Time=

P×R

S.I.×100

=

12000×13

2730×100×2

=

2

7

years

=3

2

1

years

Answer 2

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Step-by-step explanation:

Answer:

Simple \:\: Interest = \dfrac{ PRT }{100}SimpleInterest=

100

PRT

P = Rs. 1560

R = ?

T = 3 years

SI = Rs. 585

Substituting in the formula we get,

\begin{gathered}\implies 585 = \dfrac{1560 \times R \times 3 }{100} \\ \\ \implies 585 \times 100 = 1560 \times 3 \times R\\\\\implies 58500 = 4680 \: R\\\\\implies R = \dfrac{ 58500}{4680} = 12.5 \: \%\end{gathered}

⟹585=

100

1560×R×3

⟹585×100=1560×3×R

⟹58500=4680R

⟹R=

4680

58500

=12.5%

Hence the Rate of Interest is 12.5 %.