Question

find the ratio : A cylinder is filled with water upto level ‘h’. The base radius of cylinder is 3/2 times the level of the water. A solid metal cuboid of length, breadth and height 2/5 times, 1/5 times and 2/3 times of the water level respectively, is immersed in water in the cylinder. This cuboid is then taken out and another metal cuboid of length, breadth and height 1/7 times, 3/7 times and 4/5 times of the water level respectively, is immersed in the same cylinder. Find the ratio of the rise in water level in the two cases.​

Answer 1

Answer:

We know that,

Volume of cylinder =πr2h

=π×(6)2×5=180πcm3=562.5cm3

(b)  Volume of rise water in cylinder when body submerged = Volume of body

πr2H=34π(2)3

62H=34×8

H=10832cm

Hence,

rise in water level is H=10832cm

Answer 2

Answer:

Given dimensions of rectangle 22 cm ,7 cm ,5 cm and redius of cylinder vessel is 14 cm

Volume of the water risen in the cylindrical vessel == volume of the rectangular solid immersed

⇒π(14)

2

h=22×7×5⇒h=

7

22

×14×14

22×7×5

⇒h=

4

5

⇒h=1.25 cm

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