Question

find the ratio between (a-b , a+b) (-a-b,a-b)​

Answer 1

Using the section formula, we have (x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

⇒(a,b)=(

m+n

m(a−b)+n(a+b)

,

m+n

m(b−a)+n(b+a)

)

Equating, we get

⇒a=

m+n

m(a−b)+n(a+b)

⇒ma+na=ma−mb+na+nb

⇒0=−mb+nb

∴mb=nb or

n

m

=1

Hence the ratio is 1:1