Question

find the ratio between the area triangle ABC and area of triangle ACD of the given rectangle AB=4cm and BC=3cm

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Answer 2

Answer:

ratio =1:1

Step-by-step explanation:

first by Pythagoras theorem we will find the h(diagonal of ABCD or hypotenuse of triangle abc and adc h²=b²+p² =4²+3²=16+9=25 h²=25 h=√25=5 by heron's formula we will find the area s=a+b+c/2 =3+4+5/2=12/2=6 area of triangle=√s(s-a) (s-b) (s-c) =√6(6-3)(6-4)(6-5) =√6*2*3*1 =√6*6 =√6²=6cm² as the parallel sides of the rectangle are equal so ab=cd=4cm, in triangle abc and adc ab=cd(4cm) bc=ca(3cm) ac=ac (common) as ∆ abc is congruent to ∆ adc so area of ∆ abc will be equal to ∆ adc = 6cm² ratio=6:6=1:1