Question

find the ratio between the chords which are equidistant from the centre of the circle.

Answer 1

1 is the ratio of those chords which are equidistant from the centre of the circle because chords equidistant from the centre of the circle are equal

Answer 2

Hey there!

We know that,
Chords equidistant from the centre are equal.
Let the chords be AB, CD
Centre of the circle O.

Let the mid points of chords be X, Y.

Now, OX = a,
OY = b.
Also, AB = c
CD = d.

Given, OX= OY
So , a = b.

If a = b , AB = CD
That is c = d.

From the question,
AB / CD = c/d = c/c = d/d = 1

Therefore, The ratio of chords which are equidistant from the centre is 1 .

Hope helped!