Question

Find the ratio between the quantity of water coming out of two pipes with radii 2cm and 4cm in one minute,if the speed of water is 1metre/sec.

Answer 1

Answer:

Step-by-step explanation:internal diameter = 2 cm

radius = 2/2 cm = 1cm

 water flows at the rate of 0.7 m/s.

 In 1 second it covers distance = 0.7 m = 70 cm

 volume of water flows in 1 second = πr²d = 3.14 x 12 x 70 = 219.8 m³

Thus volume of water flows in 1 and half hour  = 5400 x 219.8 = 1186920 m³

radius of cylindrical tank (r) =  40 cm

Let the increase level of water = h cm

Volume of cylindrical tank = π(40)²h

Si water flows out at the rate of 0.7 m/s into a cylindrical tank. 

So,volume of water flows in 1and half hour = Volume of cylindrical tank

1186920 m³= π(40)²h

h = 1186920 / ((3.14 x (40)²)

h = 236.25 m

Hence, water rise by 236.25 m.

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