Question

find the ratio between the the area triangle abc and area triangle acd ab = 4cm and bc = 3cm
​

Answer 1

Answer:

the ratio is 1:1

please mark me as a brainliest

Answer 2

Answer:

ratio =1:1

first by Pythagoras theorem we will find the h(diagonal of ABCD or hypotenuse of triangle abc and adc

h²=b²+p²

=4²+3²=16+9=25

h²=25

h=√25=5

by heron's formula we will find the area

s=a+b+c/2

=3+4+5/2=12/2=6

area of triangle=√s(s-a) (s-b) (s-c)

=√6(6-3)(6-4)(6-5)

=√6*2*3*1

=√6*6

=√6²=6cm²

as the parallel sides of the rectangle are equal so ab=cd=4cm,

in triangle abc and adc

ab=cd(4cm)

bc=ca(3cm)

ac=ac (common)

as ∆ abc is congruent to ∆ adc

so area of ∆ abc will be equal to ∆ adc = 6cm²

ratio=6:6=1:1