find the ratio btw numbers such that their sum is 40 and their difference is 8
Answers
Answered by
1
Answer:
Let the 2 numbers be x and y with x > y
⇒
x
+
y
=
12
→
(
1
)
←
sum of 2 numbers
⇒
x
−
y
=
4
→
(
2
)
←
difference of numbers
Adding the 2 equations, term by term on both sides, will eliminate y leaving an equation in x that we can solve.
⇒
(
1
)
+
(
2
)
gives
(
x
+
x
)
+
(
−
y
+
y
)
=
(
4
+
12
)
⇒
2
x
=
16
divide both sides by 2
2
x
2
=
16
2
⇒
x
=
8
Substitute this value into equation ( 1 ) and solve for y
⇒
8
+
y
=
12
⇒
y
=
12
−
8
=
4
Thus the 2 numbers are
8
and
4
Answered by
2
Answer:
Let the two numbers be x & y
Given x + y = 40 ……. (1) & x – y = 8 … (2)
Adding 1 & 2 equations
2x = 48 ⇒ x = 24
y = 40 – 24 = 16
∴Ratio of the numbers is 24 : 16 ⇒ 3:2.
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