Question

find the ratio btw numbers such that their sum is 40 and their difference is 8​

Answer 1

Answer:

Let the 2 numbers be x and y with x > y

⇒

x

+

y

=

12

→

(

1

)

←

sum of 2 numbers

⇒

x

−

y

=

4

→

(

2

)

←

difference of numbers

Adding the 2 equations, term by term on both sides, will eliminate y leaving an equation in x that we can solve.

⇒

(

1

)

+

(

2

)

gives

(

x

+

x

)

+

(

−

y

+

y

)

=

(

4

+

12

)

⇒

2

x

=

16

divide both sides by 2

2

x

2

=

16

2

⇒

x

=

8

Substitute this value into equation ( 1 ) and solve for y

⇒

8

+

y

=

12

⇒

y

=

12

−

8

=

4

Thus the 2 numbers are

8

and

4

Answer 2

Answer:

Let the two numbers be x & y 

Given x + y = 40 ……. (1)  & x – y = 8 … (2) 

Adding 1 & 2 equations

2x = 48 ⇒ x = 24

y = 40 – 24 = 16 

∴Ratio of the numbers is 24 : 16 ⇒ 3:2.