Find the ratio by mass of elements present in molecule of ammonia(nf13) given atomic mass of n=14u,h=1u
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Hey,
atomic mass of N=14
molecular mass of H = (1*3)=3
ratio of mass of NH3=N:H3
= 14:3
HOPE IT HELPS:-))
atomic mass of N=14
molecular mass of H = (1*3)=3
ratio of mass of NH3=N:H3
= 14:3
HOPE IT HELPS:-))
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