find the Ratio in which a line segment joining (-3 4) and (3 2) in divided by line x+y-1=0
Answers
Step-by-step explanation:
Using the section formula, if a point (x,y) divides the line joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then (x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Substituting (x
1
,y
1
)=(3,4) and (x
2
,y
2
)=(−2,−1) in the section formula, we get the point (
m+n
m(−2)+n(3)
,
m+n
m(−1)+n(4)
)=(
m+n
−2m+3n
,
m+n
−m+4n
)
As the point lies on x - axis, y -coordinate =0.
=>
m+n
−m+4n
=0
=>m=4n or m:n=4:1
Step-by-step explanation:
Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then (x,y)=(m+nmx2+nx1,m+nmy2+ny1)
Substituting (x1,y1)=(3,4) and (x2,y2)=(−2,−1) in the section formula, we get the point (m+nm(−2)+n(3),m+nm(−1)+n(4))=(m+n−2m+3n,m+n−m+4n)
As the point lies on x - axis, y -coordinate =0.
=>m+n−m+4n=0
=>m=4n or m:n=4:1