Find the ratio in which line joining the points (2,4,5),(3,5,-4) is divided by yz plane
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Answer:
2 : 3 externally
Step-by-step explanation:
Hi,
Let the points be A (2, 4, 5) and B(3, 5, -4).
Given that line joining AB is divided by xz plane.
Let the ratio in which xz plane divided line AB be λ : 1
Using internal sectional formula, the point which divides AB in the ratio
λ : 1 will be (3λ + 2/λ + 1, 5λ + 4/λ + 1, -4λ + 5/λ + 1)
But since it is divided by yz plane, Any point on yz plane will have its x-
coordinate 0
=> 3λ + 2/λ + 1 = 0
3λ + 2 = 0
or
λ = -2/3
- sign indicates it is external division.
Hence, yz divided the line joining A and B in the ratio 2:3 externally.
Hope, it helps !
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