Question

Find the ratio in which line segment joining the points ( -3 .10) and ( 6, -8) is divided
by ( -1 , 6)

Answer 1

$\underline{\boxed{\bold{Question}}}$

• Find the ratio in which line segment joining the points A (-3,10) and B (6, -8) is divided  by C (-1 , 6).

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$\underline{\boxed{\bold{To \;find}}}$

• Ratio in which line segment AB is divided by point C.
• In short we have to find λ : 1

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$\underline{\boxed{\bold{Answer}}}$

Let's Start !

A = (-3 , 10)

B = (6 , -8)

C = (-1 , 6)

So let the Ratio of AC : BC = λ : 1

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So by section formula,

$\implies -1 = \frac{6\lambda -3}{\lambda + 1} \\\\\implies \lambda + 1 \implies 3 - 6\lambda \\\\\implies 7\lambda = 3-1\\\\\implies 7\lambda = 2\\\\\implies \lambda = \frac{2}{7} \\\\\implies \lambda :1 = 2 : 7$

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$\boxed{ \boxed{\bold{So \;the\; Ratio\; of\; AC : BC = \lambda : 1 = 2:7}}}$

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Hope this helps u.../

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