Math, asked by bhattomabc, 11 months ago

Find the ratio in which P(– 4, – 1) divides the segment joining A(– 7, 5) and B(– 2, – 5) from A.

Answers

Answered by sonabrainly
7

Answer:

it is a similar kind of question

Step-by-step explanation:

Let the point P(k, 7) divides the segment joining A (8, 9) and B(1,2) in the

ratio λ:1

By using internal sectional formula,

P will be of the form (λ + 8/λ+1, 2λ + 9/λ + 1)

But P is (k, 7) By comparing y-coordinate, we get

2λ + 9/λ + 1 = 7

=> 2λ + 9 = 7λ + 7

=> 5λ = 2

=> λ = 2/5

Hence the ratio in which P divides is 2 :5.

Coordinates of P are (2+5*8/7, 4+5*9/7)

=(6, 7).

Thus, k = 6

Answered by Ayushchoudhary0980
9

Answer:

sol) Let the required ratio be k:1

P( -2K-7/k+1 , -5k+5/k+1)

But p is given (-4 , -1 )

so,

-4= -2k-7/k+1

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