Find the ratio in which P(– 4, – 1) divides the segment joining A(– 7, 5) and B(– 2, – 5) from A.
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Answered by
7
Answer:
it is a similar kind of question
Step-by-step explanation:
Let the point P(k, 7) divides the segment joining A (8, 9) and B(1,2) in the
ratio λ:1
By using internal sectional formula,
P will be of the form (λ + 8/λ+1, 2λ + 9/λ + 1)
But P is (k, 7) By comparing y-coordinate, we get
2λ + 9/λ + 1 = 7
=> 2λ + 9 = 7λ + 7
=> 5λ = 2
=> λ = 2/5
Hence the ratio in which P divides is 2 :5.
Coordinates of P are (2+5*8/7, 4+5*9/7)
=(6, 7).
Thus, k = 6
Answered by
9
Answer:
sol) Let the required ratio be k:1
P( -2K-7/k+1 , -5k+5/k+1)
But p is given (-4 , -1 )
so,
-4= -2k-7/k+1
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