Find the ratio in which p(4,m)divide the line segment joiniing the points a(2,3)and b(6,-3).hence find m
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Hi Mate !!
A ( 2 , 3 )
P ( 4 , m )
B ( 6 , - 3 )
Let the point divides the AB in k : n ratio !!
AP : PB = k : n
• Using formula to find the x ( absissa ) of P
x = ( x2 k+ x1 n )/k+ n
4 = ( 6k + 2n )/k + n
4k + 4n = 6k + 2n
4k - 6k = 2n - 4n
- 2k = - 2n
k/n = -2/-2
k/n = 1/1
k : n = 1 : 1
Since the point is dividing the line in 1 : 1
hence , the point P is mid point of AB
• Coordinate of P when P is mid point !!
y = ( y1 + y2 )/2
y = ( 3 - 3 )/2
m = 0/2
m = 0
So, P ( 4 , 0 ) !!
A ( 2 , 3 )
P ( 4 , m )
B ( 6 , - 3 )
Let the point divides the AB in k : n ratio !!
AP : PB = k : n
• Using formula to find the x ( absissa ) of P
x = ( x2 k+ x1 n )/k+ n
4 = ( 6k + 2n )/k + n
4k + 4n = 6k + 2n
4k - 6k = 2n - 4n
- 2k = - 2n
k/n = -2/-2
k/n = 1/1
k : n = 1 : 1
Since the point is dividing the line in 1 : 1
hence , the point P is mid point of AB
• Coordinate of P when P is mid point !!
y = ( y1 + y2 )/2
y = ( 3 - 3 )/2
m = 0/2
m = 0
So, P ( 4 , 0 ) !!
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