find the ratio in which p(4,m) divides the line segment joining the points a(2,3) and b (6,-3). find m
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Hi there!
Given :
P (4, m) = (x, y)
A (2, 3) = (x1, y1)
B (6, -3) = (x2, y2)
Let the ratio in which P divide the line segment A and B be = k : 1
By Section formula:
Therefore,
x = kx2 + x1(1)/k + 1
4 = 6k + 2 /k + 1
4k + 4 = 6k + 2
2k = 2
k = 1
[ So, the ratio = 1 : 1 ]
Now,
y = k(y2) + 1(y1) / k + 1
m = -3 + 3 /1 + 1
m = 0/2 = 0
[ m = 0. ]
Hope it helps! :D
Cheers,
Ishaan Singh
Given :
P (4, m) = (x, y)
A (2, 3) = (x1, y1)
B (6, -3) = (x2, y2)
Let the ratio in which P divide the line segment A and B be = k : 1
By Section formula:
Therefore,
x = kx2 + x1(1)/k + 1
4 = 6k + 2 /k + 1
4k + 4 = 6k + 2
2k = 2
k = 1
[ So, the ratio = 1 : 1 ]
Now,
y = k(y2) + 1(y1) / k + 1
m = -3 + 3 /1 + 1
m = 0/2 = 0
[ m = 0. ]
Hope it helps! :D
Cheers,
Ishaan Singh
Nehaabdullah:
thnx eric
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