Question

Find the ratio in which point P(-1,y) lying on the line segment joining the points A(-3,10) and B(6,-8) divides it. Also find the value of y

Answer 1

y= -14/13
by using m1x2+m2x1/-1+y,m2y1+m1y2/-1+y

Answer 2

Answer:

The point P(-1,y) divides the line segment AB in 2:7 and the value of y is 6.

Step-by-step explanation:

Let the point P(-1,y) divides the line segment joining the points A(-3,10) and B(6,-8) in k:1.

Using section formula:

$P=(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n})$

$(-1,y)=(\frac{k(6)+1(-3)}{k+1}, \frac{k(-8)+1(10)}{k+1})$

On comparing both sides.

$-1=\frac{6k-3}{k+1}$

$-k-1=6k-3$

$2=7k$

$\frac[2}{7}=k$

It means the point P(-1,y) divides the line segment AB in 2:7.

The value of y is

$y=\frac{my_2+ny_1}{m+n}$

$y=\frac{2(-8)+7(10)}{2+7}$

$y=\frac{-16+70}{9}$

$y=\frac{54}{9}$

$y=6$

Therefore the value of y is 6.