Find the ratio in which point P whose ordinate is -3 divides the join of A(-2,3) and B(5,-15/2).
Also find the coordinates of P
Answers
Answered by
6
Answer:
ratio= 4:3 , P : ( 2, -3)
Step-by-step explanation:
given ordinate ( y- coordinate) of P = -3
let ratio be 1 : k
=> -3 = [1×(-15/2)+k×3] / (1+k)
=> -3 = (-15/2 + 3k)/ 1+k
=> -3-3k = -15/2+3k
=> 6k= (15/2) -3= 9/2
=> k = 9/12= 3/4
=> ratio= 1:3/4= 4:3
Therefore ratio= 4 : 3
coordinate of P =>x = [4×5+3×(-2)] / (4+3)
14/7= 2
P : (2,-3)
Answered by
2
Answer:
ratio= 4:3 , P : ( 2, -3)
Step-by-step explanation:
given ordinate ( y- coordinate) of P = -3
let ratio be 1 : k
=> -3 = [1×(-15/2)+k×3] / (1+k)
=> -3 = (-15/2 + 3k)/ 1+k
=> -3-3k = -15/2+3k
=> 6k= (15/2) -3= 9/2
=> k = 9/12= 3/4
=> ratio= 1:3/4= 4:3
Therefore ratio= 4 : 3
coordinate of P =>x = [4×5+3×(-2)] / (4+3)
14/7= 2
P : (2,-3)
thanks..
Similar questions
Art,
5 months ago
Math,
5 months ago
Social Sciences,
5 months ago
Physics,
10 months ago
Math,
10 months ago