Question

find the ratio in which point T(-1,6),divides the line segment joining the points P(-3,10)and Q (6,-8).​

Answer 1

Step-by-step explanation:

If two points A(x₁ , y₁) and B(x₂, y₂) are given and P is the point lies on line joining AB in such a way that AP/PB = m/n then,

Co-ordinate of point P = [(mx₂ + nx₁)/(m + n) , (my₂ + ny₁)/(m + n)]

Here, T (-1,6) divides the line joining the points P(-3,10) and Q(6,-8)

Let T divides PQ in m : n ratio then,

-1 ={m × 6 + n × (-3)}/(m + n)

-1(m + n) = 6m - 3n

-m - n = 6m - 3n

-7m = -2n

So, m/n = 2/7