Question

Find the ratio in which point T(-1,6)divides the line segment joining the points P(-3,10) and Q(6,-8).

Answer 1

If two points A(x₁ , y₁) and B(x₂, y₂) are given and P is the point lies on line joining AB in such a way that AP/PB = m/n then,
Co-ordinate of point P = [(mx₂ + nx₁)/(m + n) , (my₂ + ny₁)/(m + n)]

Here, T (-1,6) divides the line joining the points P(-3,10) and Q(6,-8)
Let T divides PQ in m : n ratio then,
-1 ={m × 6 + n × (-3)}/(m + n)
-1(m + n) = 6m - 3n
-m - n = 6m - 3n
-7m = -2n
So, m/n = 2/7

Hence, $\bf{T\:divides\:PQ\:in\:2 : 7\:ratio}$

Answer 2

Step-by-step explanation:

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