Question

Find the ratio in which the line 2x + y = 5 divides the join of A(-4, 3) and B(2, 8)

Answer 1

Answer:

line divides 2x+3y-5=0 to the segment joining (8,-9) and (2,1) in k:1

let point of intersect be (a,b)

by intersection formula

(a,b)=(2k+8/k+1  , k-9/k+1)

a=2k+8/k+1  and b=k-9/k+1

these point will also lie on line 2x+3y-5=0.hence point will satisfy this equation

2×2k+8/k+1 + 3×k-9/k+1 -5 =0

4k+16+3k-27-5k-5=0

2k-16=0

k=8

ratio will be 8:1

coordinate will be x=2k+8/k+1=24/9 and y=k-9/k+1=-1/9

Step-by-step explanation:

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