find the ratio in which the line 3x+4y-9=0 divides the line segments joining the points A(1,3) and B(2,7)
Answers
Answered by
5
Answer:
6:25
Step-by-step explanation:
Let the line 3x + 4y - 9 = 0 divides the line segment joining the points (1,3) and (2,7) in the ratio k:1
then the coordinate of the point is :
(2k+1)/(k+1) , (7k+3)/(k+1)
Since this the intersection point, it also lies on the line 3x + 4y - 9 = 0. So:
3(2k+1)/(k+1) + 4(7k+3)/(k+1) - 9 = 0
k = -6/25
Since k is negative, the line 3x + 4y - 9 = 0 , divides the line segment joining the points (1,3) and (2,7) externally in the ratio
6:25
Answered by
5
Solution
Given :-
Let
Using section formula
Where
Now put the value on formula
Now put the value of x and y on Given equation
Taking Lcm
Answer
The ratio is -6/25 or -6:25
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