Question

Find the ratio in which the line 4x + 3y – 5 = 0 divides the line joining the points
(–1, 5), and (2, 4). Also find the point of intersection.
pls answer fast

Answer 1

Answer:

Find the ratio in which the line 4x + 3y – 5 = 0 divides the line ... 5), and (2, 4). Also find the point of intersection. pls answer fast. 1 ... Add your answer and earn points.The given points are (−1,1) and (5,7).

Hence equation of the line joining the above points is

7−1

y−1

=

5−(−1)

x−(−1)

6

y−1

=

6

x+1

y−1=x+1

x−y+2=0−−−−−−−−−(1)

Equation of the given line is

x+y−4=0−−−−−−−−−(2)

The point of intersection of the lines (1) and (2) is

x−y=−2

x+y=4

2x=2

x=1,y=3

Let the point (1,3) divide the line segment joining (−1,1) and (5,7) in the ratio 1:k

By applying the section formula,

1=

k+1

k(−1)+1(5)

⇒k+1=−k+5

⇒2k=4

k=2

Hence the line joining the points(−1,1)and (5,7)is divided by line

x+y=4 in the ratio 1:2