Question

find the ratio in which the line joining (-2,5) and (-5,-6) is divided by the line y=-3. hence find the point of intersection

Answer 1

Hope this answer helps you....

Answer 2

Answer:

The point of intersection is $(\frac{-46}{11},-3)$.

Step-by-step explanation:

Let the line joining (-2,5) and (-5,-6) divided by the line y=-3 in k:1.

Using section formula:

$(x,-3)=(\frac{k(x_2)+1(x_1)}{k+1},\frac{k(x_2)+1(x_1)}{k+1})$

$-3=\frac{k(-6)+1(5)}{k+1}$

$-3=\frac{-6k+5}{k+1}$

$-3(k+1)=(-6k+5)$

$-3k-3=-6k+5$

$6k-3k=3+5$

$3k=8$

$k=\frac{8}{3}$

It means the line y=-3  divides the line joining (-2,5) and (-5,-6) in 8:3.

$x=\frac{8(-5)+3(-2)}{8+3}$

$x=\frac{-46}{11}$

Therefore the point of intersection is $(\frac{-46}{11},-3)$.