FIND THE RATIO IN WHICH THE LINE JOINING (-2,5) AND (-5,-6) IS DIVIDED BY THE LINE 2x + y = -4. HENCE FIND THE POINT OF INTERSECTION
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0
Answer:
The variable line passing through point of intersection of x+2y−1=0 and 2x−y−1=0 is x+2y−1+λ(2x−y−1)=0
⇒(1+2λ)x+(2−λ)y−(1+λ)=0
the above line meets coordinate axes at A(
2λ+1
λ+1
,0) and B(0,
2−λ
λ+1
)
Let mid point of A and B is (x,y)
⇒2x=
2λ+1
λ+1
,2y=
2−λ
λ+1
⇒
2x
1
=
λ+1
2λ+1
...... (i)
⇒
2y
1
=
λ+1
2−λ
....... (ii)
3(i)+(ii) gives
2x
3
+
2y
1
=5
∴ Required locus is x+3y=10xy
Answered by
0
Step-by-step explanation:
Find the ratio in which the line joining (-2, 5) and (-5,-6) is divided by the line 2x+y=-4. Hence find the point of intersection.
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