Question

find the ratio in which the line joining 3, 4 and - 4, 7 is divided by Y Axis also find the coordinates of the point of intersection​

Answer 1

Answer:

Let the ratio be k:1

A(3,4) ; B(-4,7) ; Y(0,y)

x=M2X1+M1X2/M1+M2

x=1(3)+k(-4)/k+1

x=0

0=3-4k/k+1

0(k+1)=3-4k

0=3-4k

4k=3

k=3/4

y=M2Y1+M1Y2/M1+M2

y=1(4)+k(7)/k+1 ...(1)

putting k=3/4 in (1)

y=4+7(3/4)/3/4+1

y=16+21/4/3+4/4

y=37/7=5.28

Hence,the ratio in which the line joining is divided by y-axis is 3:4. And, the coordinate of point of intersect is (0,5.28)

Answer 2

Answer:

Step-by-step explanation:

a(3,4) b(-4,7)

y axis means value of x =zero

let the ratio be in k :1 ,

p(0,y) is the point of intersection  on the line

by section formula,

0 =k(-4)+3(1)/k+1

0= -4k+3/k+1

k+1(0)=-4k+3

0= -4k+3

-4k = -3

k = -3/-4=3/4

therefore ,ratio=3:4

y=3(7)+4(4)/3+4

 =21+16/7

 =37/7

therefore the point are (0,37/7)