Question

find the ratio in which the line joining (5 - 6 )and (-1 - 4) is divided by x axis. also find the coordinates of the point of intersection.​

Answer 1

Answer:

sorry i am not able to understand this question

1+2 3571

2728

2728

Answer 2

The point of intersection of the line joining A (5,-6) and B(-1,-4) and the line x=0 is P(0, -26/6) in the ratio 5 : 1.

Let Y=0 divide the line joining A (5,-6) and B(-1,-4) at the point P in the ratio

k : 1. Clearly P = (0, y) for some y-coordinate y.

• Applying section formula viz., {(mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)} for P we have (0,y) ={ (-1k+5)/(k+1), (-4k-6)/(k+1)}……(1)

• Equating the x- coordinates from both sides,

                  we have 0 = (-1k+5)/(k+1)

                          => 0 = -1k+5

                              => k = 5

• Hence the line joining A (5,-6) and B(-1,-4) is divided by P or the line x=0 in the ratio 5 : 1.

To find the y-coordinate,

• Equate the y- coordinates of (1) and noting k= 5.

We then have y = (-4k-6)/(k+1)

                            = -26/6

Hence the point of intersection of the line joining A (5,-6) and B(-1,-4) and the line x=0 is P(0, -26/6)