Question

Find the ratio in which the line joining the points (6, 4) and (1, -7) is divided by x -- axis.​

Answer 1

Let the given points be A(x1, y1) = (3, 4) and B(x2, y2) = (– 2, 1). Let m : n be the ratio in which the line segment is divided by y-axis (the coordinates of the point are (0,y)) ∴ (0, y) = (mx2+mx1m+n,my2+my1m+n)(mx2+mx1m+n,my2+my1m+n) ⇒ (0, y) = (3m+3mm+n,m+4nm+n)(3m+3mm+n,m+4nm+n) ⇒ 0 = −2m+3nm+n−2m+3nm+n y = m+4nm+nm+4nm+n ⇒ – 2m + 3n = 0 ⇒ 2m = 3n ⇒ m : n = 3 : 2.Read more on Sarthaks.com - https://www.sarthaks.com/1039537/in-what-ratio-y-axis-divides-the-line-segment-joining-the-points-3-4-and-2-1

Answer 2

Step-by-step explanation:

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