Question

. Find the ratio in which the line segment joining (2, −3) (5,6) is divided by
x-axis.

Answer 1

Step-by-step explanation:

It is given that a point which is on x-axis divides the line segment joining (2,-3) and (5,6).

So, let this point be (x,0) and the ratio be k:1

So, according to the section formula:

[m1y2+m2y1/m1+m2] = y

[k×6+1×(-3)] = 0

6k-3 = 0

6k = 3

k = 3/6

k = 1/2

[m1x2+ m2x1/ m1+m2] = x

[k×5+1×2] = x

5k+2= x

5×1/2+2= x [ because k = 1/2 ]

5/2 +2 = x

So, x= 9/2

Therefore, the point (0,9/2) which is on x-axis divides the line segment joining the points (2,-3) and (5,6) and the ratio is 1:2 .