Find the ratio in which the line segment joining (-2, -3) and (5, 6) is divided by (i) x-axis (ii) y-axis. Also, find the coordinates of the point of division in each case.
(i) x-axis
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Step-by-step explanation:
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Ratio at which x-axis and y-axis cuts the line segment is 5:11.
Step-by-step explanation:
Let the ratio be m1 and m2.
Then x-axis equation will be y = 0
Section formula for point of intersection = (-2m1+5m2/m1+m2 , -3m1+6m2/m1+m2)
-5m1 + 11m2 / m1+m2 passes through y = 0
So -5m1 + 11m2 / m1 + m2 = 0
-5m1 + 11m2 = 0
11m2 = 5m1
m2/m1 = 5/11
So the ratio at which x-axis and y-axis cuts the line segment is 5:11.
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