Find the ratio in which the line segment joining(-2.-3) and (5,6 )is divided by the y axis
Answers
Answered by
3
Step-by-step explanation:
Let the ratio in which the line is divided be k:1
So,by section formula we get
(5k-2/k+1),(6k-3/k+1)
Now it is divided by the y-axis
So the point which it divides is (a,0)
Therefore,(6k-3/k+1)=0
6k-3=0
6k=3
k=1/2
So the ratio=1/2:1=1:2
Similar questions