find the ratio in which the line segment joining A(1,-5) and B(-4,5) is divided by the x-axis. Also find the co- ordinates of the point of division
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Let the ratio be k:1, where k is the required ratio in fraction form.
Therefore m1 = k and m2 = 1.
x1 = 1, x2 = -4, y1 = -5 & y2 = 5.
The dividing point lies on the x axis. So (y = 0).
Now, we get:
x = [(k)*(-4) + 1] / (k + 1) = (-4k + 1) / (k + 1).
0 = [(k)*(5) + (-5)] / (k + 1) = (5k - 5) / (k + 1).
0 = 5k - 5. 》5k = 5 》k = 1.
Therefore the ratio is 1:1.
Now, substituting the value of k to eq. 1,
x = (-4 + 1) / (1 + 1)
x = (-3 / 2).
So the coordinates are (-3/2 , 0).
Hope it helps!
Therefore m1 = k and m2 = 1.
x1 = 1, x2 = -4, y1 = -5 & y2 = 5.
The dividing point lies on the x axis. So (y = 0).
Now, we get:
x = [(k)*(-4) + 1] / (k + 1) = (-4k + 1) / (k + 1).
0 = [(k)*(5) + (-5)] / (k + 1) = (5k - 5) / (k + 1).
0 = 5k - 5. 》5k = 5 》k = 1.
Therefore the ratio is 1:1.
Now, substituting the value of k to eq. 1,
x = (-4 + 1) / (1 + 1)
x = (-3 / 2).
So the coordinates are (-3/2 , 0).
Hope it helps!
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