find the ratio in which the line segment joining A(3,‐4) and B(‐4,7) is divided by Y-axis
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Answer: Using the section formula, if a point (x,y) divides the line joining the
points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then (x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Substituting (x
1
,y
1
)=(3,5) and (x
2
,y
2
)=(−4,2) in the section formula, we get the point
(
m+n
m(−4)+n(3)
,
m+n
m(2)+n(5)
)=(
m+n
−4m+3n
,
m+n
2m+5n
)
As the point lies on y - axis, x -coordinate =0.
⇒
m+n
−4m+3n
=0
⇒4m=3n or m:n=3:4
Step-by-step explanation:
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