Question

find the ratio in which the line segment joining the point (-3,10) and (6,-8) is divided by (-1,6)​

Answer 1

Using

the section formula, if a point (x,y) divides the line joining the points

(x
1
​
,y
1
​
) and (x
2
​
,y
2
​
) in the ratio m:n, then (x,y)=(
m+n
mx
2
​
+nx
1
​

​
,
m+n
my
2
​
+ny
1
​

​
)

Let the ratio be k:1

Substituting (x
1
​
,y
1
​
)=(−3,10) and (x
2
​
,y
2
​
)=(6,−8) in the section

formula, we get (
k+1
k(6)+1(−3)
​
,
k+1
k(−8)+1(10)
​
)=(−1,6)
(
k+1
6k−3
​
,
k+1
−8k+10
​
)=(−1,6)
Comparing the x - coordinate,
k+1
6k−3
​
=−1

=>6k−3=−k−1
7k=2
k=
7
2
​

Hence, the ratio is 2:7

Answer 2

HIII MATE.... ur answer is attached...