Question

find the ratio in which the line segment joining the points (-3,10) and (6,-8) is divided by (-1,0)

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

A(-3,10) B(6,-8) C(-1,0)

1. First let the ratio k:1

2. Let the C any point on line segment AB which divides it in k:1

3. Find C

(-3+6k/k+1,10-8k/k+1)

4. Take any of the value of C equal to its real value

-3+6k/k+1 = -1

-3+6k = -k-1

7k = 2

K =7/2

5: ratio is 7:2