Question

find the ratio in which the line segment joining the points - 2 3 and 3 - 2 is divided by y axis​

Answer 1

$\textbf{Section formula:}$

$\text{The co ordinates of the point which divides the}$

$\text{line segment joining (x_1,y_1) and (x_2,y_2) internally in the ratio m:n are}$

$\boxed{\bf(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})}$

$\textbf{Given:}$

$\text{Points are (-2,3) and (3,-2)}$

$\textbf{To find:}$

$\text{The ratio in which line joining the given points divided by x axis}$

$\textbf{Solution:}$

$\text{By using the section formula,}$

$\text{The coordinates of the point which is divided by line joining (-2,3) and (3,-2) are}$

$\bf(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n})$

$(\dfrac{3m-2n}{m+n},\dfrac{-2m+n3}{m+n})$

$\text{Since it lies on y-axis, its co-ordinate is zero}$

$\dfrac{3m-2n}{m+n}=0$

$3m-2n=0$

$3m=2n$

$\implies\dfrac{m}{n}=\dfrac{2}{3}$

$\therefore\textbf{y axis divides the line joining the}$

$\textbf{given points in the ratio 2:3}$

Find more:

In what ratio is the line segment joining A(2,-3)&B(5,6) divided by x-axis also find the coordinate of the point of division.

https://brainly.in/question/7118881

Answer 2

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