Question

Find the ratio in which the line segment joining the points (-3,10) and (6,-8) is divided
by (-1,6).​

Answer 1

Step-by-step explanation:

X=-1,Y=6,X1=-3,Y1=10,X2=6,Y2=8

X=MX2+NX2/m+n

-1=m×6+n×-3/m+n

-m+n=6m-3n

-m-6m=-3n-n

-7m=-4n

m/n=4/7

Answer 2

Answer:

2:7

Step-by-step explanation:

(m1x2+m2x1/m1+m2 ,m1y2+m2y1/m1+m2)=(x,y)

X1=-3

y1=10

X2=6

y2=-8

(m1(6)+m2(-3)/m1+m2,m1(-8)+m2(10)/m1+m2)=(-1,6)

let,

6m1-3m2/m1+m2=-1&-8m1+10m2/m1+m2=6

6m1-3m2=-m1-m2

6m1+m1=3m2-m2

7m1=2m2

7/2=m2/m1

m1:m2=2:7