find the ratio in which the line segment joining the points (-3 ,10) and (6,8) is divided by (-1,6)
Answers
Answered by
5
Answer:
this is your answer.................
Attachments:
Answered by
13
Here x₁ = -3, y₁ = 10, x₂ = 6, y₂ = -8
[m(6) + n (-3)]/(m+n) , [m (-8) + n (10)]/(m+n) = (-1,6)
(6m - 3n)/(m+n), (-8m+10n)/(m+n) = (-1,6)
equating the coefficients of x and y
(6m-3n)/(m+n) = -1 (-8m+10n)/(m+n) = 6
6m - 3n = -1 (m+n)
6m - 3n = -1 (m+n)
6m-3n=-m-n
6m+m=-n+3n
7m=2n
m/n= 2/7
m:n = 2:7
So the point (-1,6) is dividing the line segment in the ratio 2:7.
please mark it brainlist please
Similar questions
Math,
4 months ago
World Languages,
4 months ago
Math,
9 months ago
Chemistry,
9 months ago
Math,
1 year ago