Question

Find the ratio in which the line segment joining the points (-3,10) and (6, -8) is divided by (-1,6)​

Answer 1

Answer: 1) The required ratio is 3 : 7

2) The point of division is (-1.5,0)

Step-by-step explanation:

Since, the point of division lies on the x axis,

Hence, the y-coordinate of the point of division = 0,

Let the ratio in which the x-axis divides the line segment having endpoints (3,-3) and (-2,7) is m:n,

By the section formula,

\frac{7\times m+(-3)\times n}{m+n}=0

m+n

7×m+(−3)×n

=0

\frac{7m-3n}{m+n}=0

m+n

7m−3n

=0

7m-3n=07m−3n=0

7m=3n7m=3n

m:n=3:7m:n=3:7

Hence, the ratio is 3 : 7,

Now, again by the section formula,

The coordinates of the point that divides are,

( \frac{3\times -2+7\times 3}{3+7}, 0)(

3+7

3×−2+7×3

,0)

(\frac{-6+21}{10},0)(

10

−6+21

,0)

(\frac{15}{10},0)(

10

15

,0)

(1.5,0)(1.5,0)

Answer 2

HIII MATE.... ur answer is attached...