Question

Find the ratio in which the line segment joining the points (– 3, 10) and (6, - 8) is divided by (– 1, 6)​

Answer 1

Answer:

2:7

Step-by-step explanation:

Consider points as A(-3,10), B(6,-8), C(-1,6)

Use section formula : \frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n}

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

Substitute the values of x_1 , x_2x

1

,x

2

so, \frac{m(-3)+n(6)}{m+n}=-1

m+n

m(−3)+n(6)

=−1

which implies, -3m+6n=-m-n−3m+6n=−m−n

-2m=-7n−2m=−7n

implies,

\frac{m}{n} = \frac{7}{2}

n

m

=

2

7

Therefore, the point divides the line in ratio 7:2